Find the discriminant of the following quadra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given quadratic equation is in the form $ax^{2} + bx + c = 0$.Comparing $4x^{2} - 12x + 9 = 0$ with the standard form,we get $a = 4$,$b = -12$

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) The given quadratic equation is in the form $ax^{2} + bx + c = 0$.Comparing $4x^{2} - 12x + 9 = 0$ with the standard form,we get $a = 4$,$b = -12$,and $c = 9$.The discriminant $D$ of a quadratic equation is given by the formula $D = b^{2} - 4ac$.Substituting the values,we get $D = (-12)^{2} - 4(4)(9)$.$D = 144 - 144$.$D = 0$.Therefore,the discriminant of the given quadratic equation is $0$.

Find the discriminant of the following quadratic equation: $4x^{2} - 12x + 9 = 0$.

Similar Questions

The value of discriminant $D$ for the equation $(x+2)(x-5)=0$ is ............

Find the discriminant of the following quadratic equation: $x^{2}-5x-14=0$.

Solve the following equation using the method of factorization and write its solution set: $\frac{x}{x+1} + \frac{x+1}{x} = \frac{41}{20}$

Solve the following equation using the method of factorization: $6(2x+1)^2 = (2x+1) + 5$

Solve the following equation using the quadratic formula,if the equation has a solution in $R$: $\frac{1}{x} - \frac{1}{x-2} = 3, x \neq 0, 2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module